This Commented CUE
demonstrates how to use the cue
command to combine multiple YAML files into a
list.
a: 1
b: "two"
c: 33.3
a: 22
b: "some string"
a: 333
c: 42
example.cue
package example
import "list"
// _inputs is the location under which we place
// each data file's contents, so that their
// contents can be accessed by the CUE in this
// file. The cue CLI -l parameter places them
// here, under a secondary key taken from the
// file's name.
_inputs: [string]: _
// Each file's contents must adhere to the #Input
// schema.
_inputs: [string]: #Input
#Input: {
a!: int
b?: string
c?: number
}
// Construct a sorted list of the input files'
// names so that our output (an ordered list) can
// remain stable no matter the order the
// filenames are provided to the cue CLI.
let sortedInputs = list.SortStrings([
for k, _ in _inputs {k},
])
// Iterate over the stable input filename list,
// and emit each input file's contents in turn.
contents: [for _name in sortedInputs {
_inputs[_name]
}]
TERMINAL
$ cue export --with-context -l '_inputs:' -l filename a.yaml b.yml c.yaml example.cue --out yaml
contents:
- a: 1
b: two
c: 33.3
- a: 22
b: some string
- a: 333
c: 42
Related content
- How-to Guide: Combining multiple YAML files into a list
- Reference: cue help flags
documents the
--with-context
and-l
flags